etc/Coding Test
[codeup] 103. 바둑알 십자 뒤집기
Jun's N
2022. 1. 2. 19:33
a = []
for i in range(20):
a.append([])
for j in range(20):
a[i].append(0)
for i in range(19):
b = input().split()
for j in range(19):
a[i+1][j+1] = int(b[j])
n = int(input())
for i in range(n):
x,y = map(int,input().split())
for j in range(1,20):
if a[j][y] == 0: a[j][y] = 1
else: a[j][y] = 0
if a[x][j] == 0: a[x][j] = 1
else: a[x][j] = 0
for i in range(1,20):
for j in range(1,20):
print(a[i][j],end = ' ')
print()
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